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Forum | ||
Author | Questions | |
asked by - Sakky016![]() |
BJT operation | |
Author | Answers | |
answered by - RSA![]() |
The main point you need to understand is that, a BJT amplifier produces a 180 degree phase shift ONLY for a sinusoidal signal. First consider the positive half cycle of the input, ASSUME A CE AMPLIFIER, so as INPUT INCREASES, BASE DRIVE (BASE CURRENT) INCREASES AND SO THE COLLECTOR CURRENT INCREASES ( as ic=hfe*ib). Now the output voltage, is nothing but your COLLECTOR-EMITTER VOLTAGE (Vce). Assuming a bias supply Vcc, and a collector-bias resistance Rc, Vc = Ic*Rc + Vce As Ic has INCREASED, to keep Vcc CONSTANT, VCE DECREASES, and so output decreases. Thus for positive half cycle of input, you get a negative half of the sinusoidal output. The same repeats for negative half cycle of the input in reverse way. Thus the OUTPUT VOLTAGE = - (INPUT VOLTAGE)*Gain. For a sinusoidal input, output is A*(-sin(wt)); -sin(wt)=sin(wt + 180). And so u get a 180 degree phase shift ONLY FOR A SINUSOIDAL SIGNAL. |